Hexadecimal number question

[danalog]

I am writing a program that needs to constantly check a clock stored in hexadecimal, and this has been far more challenging than I anticipated.

At the beginning, the program sets the clock to zero. I want the time to  last twenty seconds.

I originally had twenty in hexadecimal as uTime, but I made a program that printed out the clock every 1 second and found that the time was returned in decimal. 

I wrote a time troubleshooting program, which showed bizarre jumps - 7 to 9 is just an issue of polling the system clock at too slow an interval, but... 9 to 16? 

I believe the issue is that the scripting language requires variables to be designated as either 's' or 'u', with 's' being for a string of numbers and 'u' being for an integer.

I suspect the jumps are because when the program fetches a time from the clock (in hexadecimal) and the clock returns, say, an A or F, the program jumps to the next hexadecimal number that does not have any letters, because the stored variable cannot have any non-integer characters - even decimal points.

 

I am writing this program in Digita scripting language to run on Flashpoint Digita cameras. I do not expect a single person to know what the hell that is, but this seems, to my amateur eyes, to be a general hex to decimal conversion issue.

Since 6 numbers out of every 15 just can't be stored and processed by the program, it seems my easiest way to fix this is not to re-write the program, but to use a formula.

So if I wanted 20 seconds, I'd set the clock to 26...? 

 

Any help would be appreciated!

[Kilrah]

That looks like the clock is returning the time as BCD, precisely to avoid using A-F