Here's another problem... any ideas?
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Solved by Nineshadow,
Ok guys, found a mathematical solution, I think :
S(1)=5
S(2)=8
S(3)=14
S(2k) = 3^(k-1) * S(2) , k > 1
S(2k+1) = 3^(k-1) * S(3) , k > 1
Not too sure though.It was kind of random...
Can you guys compare these results with yours?
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