Here's another problem... any ideas?
Go to solution
Solved by Nineshadow,
Ok guys, found a mathematical solution, I think :
S(1)=5
S(2)=8
S(3)=14
S(2k) = 3^(k-1) * S(2) , k > 1
S(2k+1) = 3^(k-1) * S(3) , k > 1
Not too sure though.It was kind of random...
Can you guys compare these results with yours?
-
Featured Topics
-
Topics
-
0
-
0
-
uncanny_mac ·
Posted in New Builds and Planning0 -
0
-
kasdashd ·
Posted in Mobile Gaming0 -
0
-
zombiepunk10 ·
Posted in Phones and Tablets1 -
0
-
ITSmeJUICEE ·
Posted in Graphics Cards4 -
1
-
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now