RAID 5 Question
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Solved by wpirobotbuilder,
My understanding is that in RAID 5, for every 2 bits written to the 'useable' space, 1 parity bit gets written to the parity space using an XOR algorithm. This makes perfect sense when you have 3 (say 1TB) drives; you'd have 3TB total with 2TB of useable space and 1TB of parity data.
Thing is, you can have 4 (or more) drives in RAID 5 but you still only need 1 drive's worth of space for parity. Anyone know how this works? Surely if you store 1 parity bit for every 2 bits of data, you need 1.5TB of parity space for 3TB useable space yet somehow you only need 1TB?
The algorithm calculates a single parity block based on block data from all drives, which is stored on the parity drive. So you need one extra drive.

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