How to generalize upper and lower case input in Python

[UnspeC5d]

# Creating decision maker
import random
a = input("Magic 8 Ball, Do you want any advice?\n")
if a == "yes":
b = input("Type 'shake' to activate Magic 8 Ball\n")
if b == "shake":
c = input("Ask me anything and you shall get the answer, press enter after you have it in your mind\n")
if c == "":
print(random.choice(["Surely", "Most Probably", "Nop", "Louder man", "You might wanna think about that",
"Maybe", "Probably", "Maybe not"]))
elif b == "":
exit()
elif a == "no":
print("Okay, goodbye; See ya Later")
elif a == "":
print("Type something man")
	

 

I want to generalize the casing of the user input, whether they type in upper or lower case..

 

 

Keeping the article simple, thanks in advance..

[Nocte]

You can use the upper() and lower() methods:

 

a = "HeLLo"

print(a.lower())

>>> hello

[HunterAP]

Like Nocte said, you can use the upper() and lower() functions.

Basically you take the user input, make it lowercase using the lower() function, then compare it to your options in lowercase, like so:
 

# Creating decision maker
import random
a = input("Magic 8 Ball, Do you want any advice?\n")
if a.lower() == "yes":
	b.lower() = input("Type 'shake' to activate Magic 8 Ball\n")
	if b == "shake":
		c = input("Ask me anything and you shall get the answer, press enter after you have it in your mind\n")
		print(random.choice(["Surely", "Most Probably", "Nop", "Louder man", "You might wanna think about that", "Maybe", "Probably", "Maybe not"]))
	else:
		exit()
elif a == "no":
	print("Okay, goodbye; See ya Later")
elif a == "":
	print("Type something man")

I also added proper indentation. You also don't need the 

if c == "":

statement because the code is supposed to give a response regardless of the question.

Lastly, you didn't need the 

elif b == "":

code snippet and instead can make it into a simple "else" statement.