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Summary X, formally known as Twitter forces url substitution to X.com, making users potentially vulnerable to phishing. Twitter rolls back feature after community pushback. Quotes My thoughts This article is a few weeks old, but it would be a really interesting WAN Show discussion. This is another example of Twitter/X making sudden decisions without much thought to how it would impact the platform. At what point do users decide to leave the platform, in search of one with more stability? I love how the user base has become unpaid employees of the platform, since they have reduced their workforce so much that no one seems to see issues with these features until they make it to production. Sources https://www.bitdefender.com/blog/hotforsecurity/xs-enforced-url-substitution-to-x-com-domains-an-invitation-to-phishing-attacks/

Billy Joel released a new song for the first time in a long time and his music video features AI versions of himself singing to the song throughout the 3 distinct eras of his career. The AI was done by a company called Deep Voodoo and was pretty impressive all things considered. Video Link: Article: https://people.com/billy-joel-turn-the-lights-back-on-music-video-exclusive-8583952

This comment I posted in YouTube for WAN show named, "4K YouTube Is Getting PAYWALLED - WAN Show October 7, 2022". Hope we can have mature and real discussion about being objective on reviews. I for one doesn't believe we can be completely objective. Maybe 80 percent if we have done proper extensive research and test things extensively. But in short of that I believe we cannot foresee all of the effects in a practical scenario. Therefore I believe LTT should at least address the reasoning behind some of the things they recommend or just say in their videos with complementary articles and I believe it will be beneficial for the more enthusiastic audience. Comment as follows;

I happened to come across this absolute masterpiece, potential wan topic?

No spoilers here, if asked I can upload screenshots but I don't want to risk it knowing how Nintendo is. Maybe this can be a topic for Wan show. I haven't gathered much information on it, just downloaded it and played it so here is what I know. Basically, the game got leaked 1 week before the official release. Nintendo has been copyright-claiming gameplay videos on youtube left and right which I think is funny, and the game is fully playable on emulators(although with some major issues.) Known major issues in these emulators are some texture glitches, one of the new areas being barely unplayable cause of that(there is a workaround) and game crashes every now and then. Even with all of this, I've been able to play through the whole first area of the game in a few hours after configuring it. For what I have seen looks like some people got the physical copy of the game earlier on and ofc they started making images of them and the game got instantly on privateered websites. Maybe people can share more information here, for the time being though, this is all I know.

Catching up on the WAN show, I figured a good name for your pouch could be the Canuck Computer Container. I figure the tech sack will probably go over better though. Just make it unique call it a Texak. Then again could be a Linus Loot Locker. Alliteration is fun ya know.

Hi, hopefully Linus sees this Let me begin with some context: I'm not a lawyer, so I can't give any actual advice. I did go to college for global business, this type of thing is something I took an interest in The issue of having huge tax or other liabilities when passing the family business on is a really common issue. For example, family farms may be worth millions on paper but generate very little profit, without proper planning they are often liquidated or even worse left in a state where the government owns it and the family loses everything. (Here in the US anyway) Since typically control in companies are expressed in stock, l can tell you that in general there are 2 main components of stock: Control of the company The value of the company (derived from the control) Luckily since many people face this issue, there are often rules in place that allow the owner of the company to separate these 2 parts for tax purposes. I can think of a few scenarios that might work. I would speak to an estate planner, though I think you may have already. If they were unable to help it would be worth going for a second opinion, and if that still doesn't work you may need to go to a professional service network. This would include companies like EY, KPMG, PwC, and Deloitte. I think an estate planner should be able to do it, but someone should be able to make it so that if your kids don't have to pay for the entire thing if you just want the company to continue functioning. Feel free to leave a comment below if you have some thoughts

Summary BMW to allow subscriptions for in car features, just like Linus predicted. Like heated seats and steering wheels in uk for £15 and £10 per month. Quotes My thoughts This would make cars heavy and less efficient for no reason if you don't want or need these features. Linus predicted this may become a thing, just like most he thought it would be Tesla who would introduce this but looks like BMW may have beaten them to it. I could see how some may like it on the second hand market letting you add features without the higher cost of having to install the equipment but I think most people are against this. Sources https://www.bbc.co.uk/news/technology-62142208.amp https://news.sky.com/story/bmw-criticised-for-putting-heated-seats-behind-a-paywall-12651279 https://www.theverge.com/2022/7/12/23204950/bmw-subscriptions-microtransactions-heated-seats-feature

The following is a conversation with an AI assistant. The assistant is helpful, creative, clever, and very friendly. Human: Hello, who are you? AI: I am an AI created by OpenAI. How can I help you today? Human: I wanna know how change in entropy of a system become positive just because equilibrium constant of partial pressure became smaller due to temperature increase. Th reaction is all gas and it's an exothermic reaction overall. AI: The change in entropy of a system becoming positive when the equilibrium constant of partial pressure becomes smaller due to an increase in temperature is a result of the fact that, as temperature increases, there is an increase in the number of particles present in the system. This means that more energy is being used to move the particles, resulting in a positive change in entropy. The exothermic nature of the reaction also means that the reaction is releasing heat into the system, further increasing the number of particles present, and thus the entropy of the system. Human: What happens to the entropy of the surround? AI: The entropy of the surroundings also increases as a result of an exothermic reaction. Heat is transferred from the reaction system to the surroundings, raising their temperature and therefore increasing the entropy of the surroundings. Human: can you mathematically show this to me? AI: Absolutely! The change in entropy of the system, $\Delta S_{system}$, is given by the equation: $\Delta S_{system} = \frac{q_{reaction}}{T}$ Where q is the heat transferred to the system during the reaction and T is the temperature of the system. The entropy of the surroundings, $\Delta S_{surround}$, is given by the equation: $\Delta S_{surround} = \frac{q_{reaction}}{T_{surround}}$ Where q is the heat transferred from the system during the reaction and T_surround is the temperature of the surroundings. Human: can you redo this but in terms of Enthalpy AI: Absolutely! The change in enthalpy of the system, $\Delta H_{system}$, is given by the equation: $\Delta H_{system} = q_{reaction}$ Where q is the heat transferred to the system during the reaction. The enthalpy of the surroundings, $\Delta H_{surround}$, is given by the equation: $\Delta H_{surround} = -q_{reaction}$ Where q is the heat transferred from the system during the reaction. Human: CO(g) + 2H₂(g) ⇌ CH₃OH(g) AI: The equation you provided describes the reaction of carbon monoxide and hydrogen to form methanol. This is an exothermic reaction, meaning that heat is released into the system and its surroundings. Therefore, the entropy of the system and its surroundings should increase as a result of this reaction. Human: yes, when the temperature of the system is increased from 500 K to 700 K. the value of Kp is smaller, why? AI: The value of Kp being smaller when the temperature of the system is increased from 500 K to 700 K is due to the fact that at higher temperatures, the reaction is more likely to shift in favor of the products side of the equation. This is because more energy is available to drive the reaction at higher temperatures, resulting in a smaller Kp value. Human: but since Kp is smaller so reaction does not go as far to right, isn't it? AI: Yes, that is correct. Since Kp is smaller when the temperature of the system is increased from 500 K to 700 K, the reaction does not go as far to the right, meaning that some reactants may remain after the reaction is finished. Human: so wouldn't the reaction favour backward reaction? AI: Yes, the reaction may favor the backward reaction as the equilibrium constant of the reaction decreases. However, that doesn't necessarily mean that the reaction will be driven in the direction of reactants, as the decrease in Kp could be offset by other factors such as the increase in temperature. Human: okay if the Temperature increases, change in entropy of the surrounding should decrease right? And if it decreases what happens to the entropy of the system? In context of that reaction i showed you earlier which is at equilibrium. AI: The increase in temperature of the system and its surroundings will cause an increase in entropy for both the system and the surroundings. This is due to the fact that as temperature increases, the number of particles present also increases, resulting in an overall increase in entropy. In the context of the reaction you provided earlier, this should result in a positive change in entropy for both the system and the surroundings. Human: okay so the yield of the product will decrease but not by much, if i got all this right. AI: Yes, that is correct. The increase in temperature of the system and its surroundings will result in a decrease in the yield of the product since the equilibrium constant of the reaction decreases. However, the decrease in yield should not be significant if the temperature is increased by a small amount. Human: A temperature Increase from 500 K to 700 K is a small change or a big change in this context. AI: In this context, a temperature increase from 500 K to 700 K would be considered a relatively large change. This is because, although the absolute difference between the two temperatures may not be significant, the rate at which the reaction will shift in favor of the products side is significantly increased by increasing the temperature of the system by such a large amount. Human: Oh because there is more reactants then products, it will shift to the right regardless to the fact that it is an exothermic reaction, or am i wrong? AI: You are correct. Increasing the temperature of the system from 500 K to 700 K will result in a shift of the reaction towards the products side, regardless of the fact that it is an exothermic reaction. This is because, although the reaction releases heat into the system, the increased temperature causes the rate at which the reaction shifts in favor of the products side to be significantly higher than the rate at which the reaction shifts in favor of the reactants side. Human: But then why has the equilibrium constant decreased if it indeed has shifted to the product side? AI: The decrease in the equilibrium constant is due to the fact that at higher temperatures, more reactants are being converted into products than at lower temperatures. This means that the number of particles of products will increase faster than the number of particles of reactants, resulting in a decrease in the equilibrium constant. Human: you mean to say molar fraction of reactions has decreased compared to the product? But that would make the ratio of the equilibrium constant increase rather than decrease. can you show me a math that can help me see this. AI: Yes, you are correct. The molar fraction of reactants has decreased compared to the product. Mathematically, this can be represented as follows: $K_p = \frac{[CH_3OH]}{[CO][H_2]^2}$ Where [CH_3OH] is the molar fraction of methanol, [CO] is the molar fraction of carbon monoxide, and [H2] is the molar fraction of hydrogen. As the temperature increases, the molar fractions of reactants will decrease compared to the molar fraction of the product, resulting in a decrease in the value of Kp. Human: can you show me a numerical example? I cannot seem to replicate it on my calculator AI: Sure! Let's assume we have a reaction of 1 mol of carbon monoxide and 2 moles of hydrogen at 500 K, which results in a Kp value of 0.2. If the temperature is then raised to 700 K, the Kp value would decrease to 0.12. This can be graphically represented as follows: At 500K => Kp = 0.2 At 700K => Kp = 0.12 Human: can you go into more details? AI: Of course! As the temperature increases, the particles in the system have more energy, allowing them to move more quickly and react more efficiently. This increases the rate at which the reaction shifts towards the products side, resulting in a decrease in the equilibrium constant. At the same time, since the reaction is exothermic, heat is being released into the system and its surroundings, increasing the number of particles present. This further increases the rate at which the reaction shifts towards the products side, and thus the equilibrium constant decreases. Human: Numerically i meant. AI: Sure! Let's assume we have a reaction of 1 mol of carbon monoxide and 2 moles of hydrogen at 500 K, which results in a Kp value of 0.2. If the temperature is then raised to 700 K, the Kp value would decrease to 0.12. This can be calculated mathematically as follows: At 500K => Kp= $\frac{[CH_3OH]}{[CO][H_2]^2} = \frac{1}{1 \ x \ 0.5^2} = 0.2$ At 700K => Kp= $\frac{[CH_3OH]}{[CO][H_2]^2} = \frac{1}{1 \ x \ 0.7^2} = 0.12$ Human: can you make it more simpler? AI: Sure! The change in the equilibrium constant can be simplified to: $K_p = \frac{1}{[CO][H_2]^2}$ Where [CO] is the molar fraction of carbon monoxide and [H2] is the molar fraction of hydrogen. As the temperature increases, the molar fractions of reactants will decrease compared to the molar fraction of the product, resulting in a decrease in the value of Kp. Human: but you have not considered methanol in your calculation. AI: You are correct, I have not considered methanol in my calculation. However, the molar fraction of methanol is constant throughout the reaction, so it does not affect the change in the equilibrium constant. The only factor that affects the change in the equilibrium constant is the molar fractions of the reactants, which decrease as the temperature increases. Human: can you explain to me how does it stays constant AI: Sure! The molar fraction of methanol stays constant throughout the reaction because it is a product of the reaction, meaning that it is not consumed in the reaction and thus its molar fraction does not change. The only factor that affects the change in the equilibrium constant is the molar fractions of the reactants, which decrease as the temperature increases. Human: But this is a reversible reaction AI: Yes, this is a reversible reaction. This means that, although the molar fraction of methanol stays constant throughout the reaction, the reaction can still shift in either direction depending on the temperature and other factors. At higher temperatures, the reaction is more likely to shift in favor of the products side of the equation, resulting in a decrease in the equilibrium constant. Human: But i am not convinced that methanol stays constant AI: That's understandable. To further explain why the molar fraction of methanol stays constant throughout the reaction, it is important to understand that methanol is a product of the reaction and not a reactant. This means that it is not consumed in the reaction and thus its molar fraction does not change. The only factor that affects the change in the equilibrium constant is the molar fractions of the reactants, which decrease as the temperature increases.

source1 source2:video source3:whatsapp - source 1 So Facebook invested heavily in India which is really getting really scary now. For those of you who aren't from India let me clear the situation up. Jio (4g LTE cellular network) is owned by Reliance industries and the man at the top is Mukesh Ambani (guy in the video in source 2 )who's one of Asia's richest people. He started Jio publicly in September 2016 and in 4 years already is India largest network operator with 370 million plus subscribers (3rd largest in the world) He did this by basically destroying the competition by giving away totally free sim cards and charged nothing for LTE for around a year or more. Because of him alone the LTE rates in India are cheap. for eg. heres a monthly plan for jio 2.61 USD gives you 1.5 GB data/day after that slower speed i.e 42GB/month unlimited jio to jio calling 1000 minutes free 100 sms/day free jio apps - free streaming apps with quite a lot of content. tv shows, music, among other things. Back to Facebook now. Facebook bought whatsapp a while back which currently has around 2 billion users and of those more than 400 million just in India. - data from source 3 Whatsapp is everywhere in India. Even the local grocery seller (not a shop) Whatsapps the price of veggies and you can buy them by replying. he will deliver those to your doorstep. Facebook already tried digital payments with Whatsapp which failed badly. The video in source 2 talks about integrating Whatsapp with Jio and allowing digital payments. This has a HUGE potential. Jio is already at a position where it will dominate the network operator market. There are only 3 major players out of which one is on the verge of collapse (Vodafone India) the combination of both Whatsapp and Jio is deadly as the customer base is already quite huge and may not even have many options to choose otherwise. We all know Facebook cant be trusted at all. I really fear giving such sensitive data to Facebook. (This could be a wan show topic i don't know if there's a thread to post these topics somewhere so correct me if i'm wrong.)

https://medium.com/@areejsyed/intel-claims-that-the-core-i3-8145u-is-better-than-the-amd-ryzen-7-3700u-no-really-were-not-9442db9bd8c6 The plot thickens

I thought this would make a good Wan Show topic for this week. So here you go! AT&T is trying to get customers to upgrade their phones to 5G ones by sending them emails about devices that were bought before they could support 5G. I myself received one of these messages in correlational to my still, very capable Razer Phone 1. I was furious when I thought I was going to have to replace a phone I had just gotten 6 months ago. While I turns out that customers will not need to buy new phones for the network until 2022, I think that this matter should be addressed now before too many people buy something that they don't need. The Verge did a pretty good article on the subject, Here. The main point that I think all paying customers need to know is that this is seriously a bunch of baloney to get customers to buy "Brand New Shiny Phones" for the launch of 5G.

Congresswoman from New York Alexandria Ocasio-Cortez requested a stop to using military funds on twitch.tv. she doesn't want anyone to be recruited from twitch. https://www.foxbusiness.com/technology/aoc-wants-the-military-to-stop-recruiting-with-esports

Really creepy, give it a read and watch out for any unsecured cameras you guys may have. http://arstechnica.com/security/2016/01/how-to-search-the-internet-of-things-for-photos-of-sleeping-babies/

Hey i just found this article and i thought it would be interesting on the WAN show. Not really sure where to post but i hope this is correct. The article is about how fraud is making Zalman file bankruptcy. This is pretty crazy and i thought i would share it with you guys. http://www.anandtech.com/show/8697/corporate-fraud-drives-zalman-to-bankruptcy