ohJey

this is why lane splitting is legal here in California

yeah he was sideswiped and was just bruised up

my friend totaled his bike 2 days ago lane splitting... luckily he didn't total his life

My friend has a 1993 Impreza wagon that needs a transmission, so I might just have another subaru

nono, when I bought it I sold the rest of the parts off the car and it's just a shell in my friends back yard now

yeah the cars are really cool, like giant legos just mix and match parts just get a wheel boot and a steering lock that should eliminate like 99.5% of thieves (this is a picture when I bought the car)

yeah it power wheelies easy i want to get a short clutch so I can learn to clutch wheelie

yeah it is but us Americans call it the FZ-07 I think it has to do with the yamaha fazer .

the car was only insured with liability, I got nothing

It's all good, I switched to two wheels now

Idk if you guy remember my car, but this is what's left of it after being stolen

CAR IS BACK! I don't know if this is allowed, but my car was stolen in Cathedral City, California It's a 1998 Subaru Impreza Car was spotted in Desert Hot Springs on DILLON ROAD and in Palm Springs on CALLE ENCILIA near the Hilton Hotel, heading south If you know anyone from DHS/PALM SPRINGS please help me out! The car is hard to miss http://imgur.com/a/ND0Fv

I'm looking at the previous "no". If the previous statement (b^2-4ac>=0) is "no", then how could (b^2>>4ac) be "yes"?

Is this a logic error? This is the flow chart my teacher gave me for a program that solves the quadratic formula how could b^2-4ac not be >= 0 and b^2 be much greater than 4ac at the same time?

(for your application)

1. anything newer than office 2007 doesn't work 2. adobe software wont work or it wont use your hardware properly it's best to stay on windows

wow... I did i = i-number-1 and it worked

the problem is I'm trying to subtract the last dice roll and I can't figure out how to do it the lands.back() was me trying to get the last number in the vector... but it gives me random numbers

I'm trying to make the program simulate dice rolls... the dice add up until 100. If the dice "rolls" and the number is over 100, the roll is subtracted until 100 is landed upon. Ex: 98+4=102, then 102-4=98, then it keeps "rolling" and subtracting until 100 is landed on #include <iostream> #include <ctime> #include <cstdlib> #include <vector> using namespace std; int main() { srand(time(0)); int number, tries{0}; ///the number that the dice lands on vector<unsigned int> lands(5); for(int i=0; i<=100; ++i) { if(i<100) { number = rand()%6; i=number+i; cout << "i: " << i << endl; ++lands[number]; } if(i>100) { i=i-lands.back(); ///need help here cout << "lands.back(): " << lands.back() << endl; ///debugging cout << "i: " << i << endl; } else if(i==100) { cout << "i: " << i << endl; cout << "Done!" << endl; } } tries = lands[0]+lands[1]+lands[2]+lands[3]+lands[4]+lands[5]; cout << "Tries: " << tries; cout << "\nAfter " << tries << " throws the lands are: " << "\n#1= " << lands[0] << "\n#2= " << lands[1] << "\n#3= " << lands[2] << "\n#4= " << lands[3] << "\n#5= " << lands[4] << "\n#6= " << lands[5]; }

actually... I fixed it by adding the line studentID=sqrt(studentID); cout << studentID; I plugged 2742724836164 into a calculator and divided by 524142 and the answer was 524142, so it wasn't doing the square root anyways, thanks a lot

sorry, late reply but I got this

it's ok no hard feelings. I think I might understand now, but feel free to check it out

yeah... I'll have to ask my teacher... If there was a way to store the remainders after each modulus I think that would help

Students in my class have already done it. If you look at the program the number is encrypted by squaring it, doing modulo 90, and adding 33 to that character. Now I need to know how to reverse it.

I need to reverse the "encryption" done in this program cloudflare is acting up so I have to post as a pastebin http://pastebin.com/SyCS8CZh