Deprecated

MVC is the way to go for this

GUI's definitely slow down users who know what they want to happen and how to do it. No GUI is going to offer the same power as a good CLI shell

Vim is to good Vim > Emacs

What kind of Unix Hacker needs a UI?

a lot of unix users use many different flavors of unix actually. Macs dont really offer any advantage in using their operating system for unix hackers. Dont get me wrong, it's not a bad os, it just isnt that much better, if any, to other unix distros. For a Unix user it mostly will come down preference. Also there is several GIT GUI interfaces for linux ( http://git-scm.com/downloads/guis )

stash in GIT?

checkout from your repo through your ide or install git and do it through cli

you can only refer to line within the while loop in the prompt method. That's where its in scope

sounds like you will have to write your own shouldnt be to hard, read up on DAO's and RMI and you should be good to go

/** * Created by Tyler on 2014/10/08. */ public class Hotel { private boolean[] rooms; public Hotel(final int numRooms) { rooms = new boolean[numRooms]; } public void checkIn(int roomNum) { if (rooms[roomNum]) { System.err.println(String.format("Room #%d is already occupied!!", roomNum)); } else { rooms[roomNum] = true; System.out.println(String.format("Room #%d is now occupied", roomNum)); } } public void checkOut(int roomNum) { if (rooms[roomNum]) { rooms[roomNum] = true; System.out.println(String.format("Room #%d is now empty", roomNum)); } else { System.err.println(String.format("Room #%d is already empty!!", roomNum)); } } public boolean isOccupied(int roomNum) { return rooms[roomNum]; } } As simple as i can make it to demonstrate the idea

Since we are reading a string now there really isn't any input mismatch problems (numbers can easily be represented as strings). Also Scanner.nextLine doesn't throw that exception

Sounds like business requirements so you would probably find a good answer from people who have worked at hotels

private static String promptUserYesNo(String prompt) { while (true) { System.out.print(prompt); String line = scanner.nextLine(); if ("Yes".equalsIgnoreCase(line) || "No".equalsIgnoreCase(line)) { return line; } System.out.println("Invalid input, valid inputs are Yes or No."); } }

private static int promptUserInt(String prompt) { while (true) { try { System.out.print(prompt); return scanner.nextInt(); } catch (InputMismatchException e) { System.out.println("Invalid input, please type an integer."); } finally { scanner.nextLine(); } } } sorry it probably just needs to clear the buffer

if the user input is an integer then the integer is returned from the method which will cause the flow to leave the loop. If it is not an integer then an exception is throw and caught so the error message shows and it goes back to the prompt