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Quick help with Polynomial problem(not HW, just really confused on a problem)

Ok so i was looking through my book and i saw the problem

Write a polynomial function with zeroes -2 and 1+i, that also fits f(-2)=4

The zeroes should be -2 1+i and because 1+i is a complex number, another zero would be 1+i.

How could f(-2)=4 when -2 is a zero???

can anybody help me out with this?

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Takes me back to my pre-calc days

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Takes me back to my pre-calc days

so help, much wow

I can help with programming and hardware.

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so help, much wow

lol, i'm doing it on paper right now, I just thought I would reminisce before I started. I'm a bit rusty but leme try and figure it out

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lol, i'm doing it on paper right now, I just thought I would reminisce before I started. I'm a bit rusty but leme try and figure it out

Thanks man

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lol, i'm doing it on paper right now, I just thought I would reminisce before I started. I'm a bit rusty but leme try and figure it out

I'm thinking maybe you can add more zeroes, but i just don't think it's possible, if while x is -2 y is zero, how could f(-2) = 4

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I think there must be a mistake in the question

sudo chmod -R 000 /*

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I think there must be a mistake in the question

that's what I'm thinking

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does it mean maybe x-2 would be a zero, therefore f(2)=0??? idk its been awhile

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does it mean maybe x-2 would be a zero, therefore f(2)=0??? idk its been awhile

no it said that a zero was -2, not a factor was x-2

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The zeros would be x=-2 and x=1+i so rearrange them to equal zero, multiply them out and equate coefficients.

Edit: just realised that that is basically what you said in the post. Yep looks like the question is bust.

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The zeros would be x=-2 and x=1+i so rearrange them to equal zero, multiply them out and equate coefficients.

Edit: just realised that that is basically what you said in the post. Yep looks like the question is bust.

thanks for the help guys

I can help with programming and hardware.

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