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Images of pins for z370 & z270

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1 hour ago, Hunter259 said:

Only if the motherboard makers know that. It can be completely up to them whether or not to put traces on unused pins.

no not it's not. you don't leave loose ends on a chip. they have to either be tied to ground or VCC if they are unused. you can't just leave them floating that's not how it works

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3 hours ago, SquintyG33Rs said:

no not it's not. you don't leave loose ends on a chip. they have to either be tied to ground or VCC if they are unused. you can't just leave them floating that's not how it works

If a pin is completely unused then it wouldn't need to even be grounded. It's unused. There's no reason it would have be apart of any electrical circuit. If it had VCC tied to in then it would be in use. If it was grounded then it is for no actual reason.

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What I don't get is how Intel can have the foresight to design the 1151 socket pin layout which is completely compatible with Z170 and Z270 with reserved pins in case they are needed in the future and yet here we are with Z370 which has the exact same socket and layout with no plans from AiBs or Intel to support compatibility between the two/three platforms.

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8 hours ago, samcool55 said:

Thing is, with tech it's basically 100% electricity to heat.

No, 100% electricity to heat would be a space heater (and even then, it's never 100%).  The heat is what's generated because the process isn't 100% efficient, and some energy becomes lost and dissipated as.......*drum roll please* heat.

8 hours ago, samcool55 said:

Also TDP is not a temperature thing, it's watts which is a form of energy...

Energy which is dissipated as heat.  The 'T' stands for 'Thermal', after all.  Think of it along the lines of the 80+ ratings on PSUs.  The lower rated PSUs don't use all of the energy they consume.  The energy that's lost becomes heat.  While a higher rated PSU will lose much less energy, and thus generate less heat.  The amount of energy lost as heat translates into TDP.

 

This is the same thing on CPUs, it's the lost energy because of the inefficiencies in the process that leads to heat generation, not the power consumption itself.

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1 hour ago, Hunter259 said:

If a pin is completely unused then it wouldn't need to even be grounded. It's unused. There's no reason it would have be apart of any electrical circuit. If it had VCC tied to in then it would be in use. If it was grounded then it is for no actual reason.

that's just not how electricity works

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10 hours ago, Bananasplit_00 said:

dosent change my conclusion that these extra pins are not needed, oh and Kabylake at stock sits in its power draw more or less smack dab on that TDP, and moveing forward  id expect the same from them.

Power Delta (Long Idle to OCCT)

Dude if you look at the i5 with the same tdp it only draws 68w so it is still flawed. I would say it is just coincidence.

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15 hours ago, AresKrieger said:

Wish I did as it is hard to prove a point to someone without them

yah its annoying that there are so few actiual messurements of how much power a CPU will draw beyond the TDP

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8 hours ago, SquintyG33Rs said:

that's just not how electricity works

Um. Yes it does? I could design something that only needs 2 pins but make a socket that has 40. Those other 38 have no electrical significance and thus would not need any actual connections to anything.

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5 hours ago, VegetableStu said:

Are they all the same power rail inside the substrate? o_o

In this case it's magic. Probably should have picked a bigger number than 2 if I'm going to use 40 for the total amount :P

 

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