Bash: Composing all variations of 9 letters

[MrKickkiller]

Hi

 

i'm looking for a simple way to compose all variations of 9 letters of which there must at least be 4 used and 1 (the fifth argument to the script) must always be used.

 

I had already been thinking of making a 9 nested for loops, but I don't think that will do the trick since it is not very scalable...

 

Thx.

[Cheesebaron]

You only need two loops to generate all permutations.

[mikebald]

I'm going to try and reword this to see if I understand what you're looking for.

 

You want a script that takes 5 arguments and generates a string of length 9 for every permutation of the input arguments. Additionally, the output string must always contains at least 1 copy of the 5th argument.

 

Example Input:

 

A,B,C,D,Q

 

Example Output:

 

AAAAAAAAQ

AAAAAAABQ

...

DDDDDDDDQ

...

QQQQQQQQQ

 

Is this what you're asking for?