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Survey : 5.25 drive bay Usage

Survey : 5.25 drive bay usage  

167 members have voted

  1. 1. Do you still use / want to use a 5.25" drive bay (not only optical drive, but anything that fits in 5.25 bays)?

    • Still use in 2019 and proud of it
      73
    • Maybe want to use, depends on what I can find
      36
    • No, what the hell? is it 1995 again?
      58
  2. 2. If you selected option 1 or 2 above, what would you use a 5.25 drive bay for?

    • Slick internal stats monitor (temperature, fan speed, power usage, etc.)
      27
    • Optical drive (DVD / Bluray)
      84
    • Memory card reader
      38
    • Fan / RGB - controller
      21
    • Add USB ports (type A or C) on the front
      33
    • DIY projects / Other
      37
    • voted no : not applicable
      52


I have two unused 5.25 bays on my Fractal Design R5 case.  I don't see any need for them now and probably the future.  If I need to read a CD/DVD, I plug in an external USB drive.  My card photo card readers are all USB external.  My old four way card reader was rendered defunct by the new cards that Nikon and Sony are using in the newer mirrorless cameras.  If I had installed a  card reader in the 5.25 bay, it would have to be pulled out for a newer model.

Workstation PC Specs: CPU - i7 8700K; MoBo - ASUS TUF Z390; RAM - 32GB Crucial; GPU - Gigabyte RTX 1660 Super; PSU - SeaSonic Focus GX 650; Storage - 500GB Samsung EVO, 3x2TB WD HDD;  Case - Fractal Designs R6; OS - Win10

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I removed all the 3.5" mounts and mounted my HDD in the 5.25" bay. 

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I would use one if my case had it since I found a 5.25" bracket with big rubber dampeners for a 3.5" HDD.

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  • 2 weeks later...

I finally pulled the trigger and bought a case with no 5.25 bay... But I have hope I can mod it and 3d print something to fit my all-in-one card reader.

Dear diary: Today was not tomorrow and not yesterday, which I think is nice...

//Overengineering example:

#include <iostream>
#include <string>

using namespace std;

int main()
{
  string s = "Hello World";
  for (int i = 0; i < s.length(); ++i)
  {
      cout << s[i];
  }
  return 0;
}

 

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