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Does the SHC of water have to be converted to J/Kg/C if the temp. change is in C?

NeatSquidYT
By NeatSquidYT
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Hi,

Title says it all.

 

The question is "A plastic beaker containing 0.080kg of water at 15 degrees celcius was placed into a refrigerator and cooled to 0 celcius in 1200s. Calculate how much energy each second was removed from the water in this process"

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Posted

Temp (in C) = energy?

If so, 1 degrees C gets removed every 80 seconds..

 

Am I understanding your question?

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Er, it's been a while since I did thermodynamics, but here goes.

 

It takes 1 calorie (lower case c not Calorie as in 1000 calories) to raise/lower 1C of 1gram of water. So in this case, 80 grams of water is lowered 15 C (assuming it doesn't turn to ice, because that involves other calculations), 80*15=1200 calories (convenient). 1200 calories were removed over 1200 seconds, which meant that the rate of heat loss (or energy loss) is 1 calorie per second.

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Posted
  • Author

Temp (in C) = energy?

If so, 1 degrees C gets removed every 80 seconds..

 

Am I understanding your question?

No, not really. I'll just leave it for now

 

Er, it's been a while since I did thermodynamics, but here goes.

 

It takes 1 calorie (lower case c not Calorie as in 1000 calories) to raise/lower 1C of 1gram of water. So in this case, 80 grams of water is lowered 15 C (assuming it doesn't turn to ice, because that involves other calculations), 80*15=1200 calories (convenient). 1200 calories were removed over 1200 seconds, which meant that the rate of heat loss (or energy loss) is 1 calorie per second.

The question in the post has nothing to do with calories, but thanks anyways

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