Help [Java]

[PugoOfficial]

How do I make the program confirm if the input of the user is correct or wrong(Username and Password) ? Appreciate it if someone actually showed me the solution .. The Aim of the program is to make the user to register(if they don't have an account yet) then log in then exit.

import java.io.*; public class Login { 	 public static void main (String [] args) throws IOException { 	 	 BufferedReader fc = new BufferedReader(new InputStreamReader(System.in)); 	 	  	 	  String RegUsers[] = new String[1]; 	 	  String RegPass[] = new String[1]; 	 	  	 	 boolean loop = true;			while(loop == true) {										boolean choose = true;						while (choose == true) { 	 	  	 	 System.out.println("[1]Register a new Account    [2]Login an existing Account      [3]Exit"); 	 	 int z = Integer.parseInt(fc.readLine()); 	 	  	 	 if (z == 1) { 	 	   	 	   int x = 0; while(RegUsers[x] !=null) { x++; }  	 	    	 	   System.out.println("Enter your username: "); 	 	    	 	    RegUsers[x] = fc.readLine(); 	 	     	 	     System.out.println("Enter your password: "); 	 	      	 	      RegPass[x] = fc.readLine(); 	 	       	 	       for(int i = 0; i<RegUsers.length; i++) {  	  			 System.out.println(RegUsers[i]); 	  			 } 	  			 }			 else if (z == 2) {				System.out.println("Enter your username: ");				String user = fc.readLine();								System.out.println("Enter your password: "); 	 	     	String pass = fc.readLine();				}							else {				System.out.println("Program Terminated!");				choose = false;				}							loop = false;								}			}		}	} 

[Midnight]

I'm not giving you solutions, lol. Just compare the strings with the equals() method.

 

Also, I'm not sure why you're using an String array of size 1. It's impractical.

[PugoOfficial]

I'm not giving you solutions, lol. Just compare the strings with the equals() method.

 

Also, I'm not sure why you're using an String array of size 1. It's impractical.

 

Well I'm just using the size of 1 for testing I could change that anytime you know

[KuroSetsuna29]

It also helps if you keep good formatting to help read code, it can be very confusing when it keeps indenting.

 

If you are not encrypting passwords, then you can just do as Midnight suggested, use .equals(), like so:

for (int i = 0; i < RegUsers.length; i++){    if (RegUsers[i].equals(user)) //Up to you if case sensitive matters, use equalsIgnoreCase()    {        if (RegPass[i].equals(pass))        {            // correct password        } else {            // wrong password        }        break;    }}

There are probably much better ways of doing this, but this is the quick and dirty solution.

Edited March 5, 2015 by KuroSetsuna29