Python Question

[X1XNobleX1X]

Hello forums

I'm having trouble with Python:

Here is what I have:

 

temp = int(input("Temperature: "))

while temp != 42:

  if temp < 42:

     print("Too cold!")

  if temp > 42: 

    print("Too hot!")

  if temp == 42:

    print("Just right")

    

I'm very frustrated it's suppose to this this:

 

Here is the example.

 

Temperature: 12

Too cold!

Temperature: 36

Too cold!

Temperature: 39

Too cold!

Temperature: 46

Too hot!

Temperature: 51

Too hot!

Temperature: 43

Too hot!

Temperature: 42

Just right!

 

But it doesn't !

 

Thanks for all the help!

 

 

[madknight3]

You need to accept the input inside the while loop or else it will only ask you once.

[Marvzl1357]

change the first line to 

while True:     temp=raw_input ("Temperature: ") 

then everything else

you know what? I'll just change it to how I see it works:

while True:  temp=raw_input ("Temperature: ")  if temp < 42:     print("Too cold!")  elif temp > 42:     print("Too hot!")  elif temp == 42:    print("Just right")  else:    print("probably dead...")

[madknight3]

change the first line to 

while True:     temp=raw_input ("Temperature: ") 

then everything else

If he wants the loop to exit when 42 is entered, then there's no need to make it an infinite loop.

[X1XNobleX1X]

          

 

If he wants the loop to exit when 42 is entered, then there's no need to make it an infinite loop.

Tha'ts what I want it to do,

What do I need to change?

[Marvzl1357]

 

          

 

Tha'ts what I want it to do,

What do I need to change?

 

welll....sorry but I don't know how to break a loop upon a specific input...

But what I proposed doesn't work anyway, I fixed it a little. Turns out the use of greater than/less than signs specifically require you convert the input to a floating number. my bad, I didn't notice the first line of your code...

Basically everything else is working except the loop parameters. I'm sorry, I'm not helping much...

temp = int(input("Temperature: "))if temp ==42:    print ("Just right")if temp < 42:    print ("Too cold")if temp > 42:    print ("Too hot")    

[rashdanml]

If he wants the loop to exit when 42 is entered, then there's no need to make it an infinite loop.

An alternate approach is to use an infinite loop, but using a break; statement for the condition if temp==42, after printing out "Just right". 

[Kiwi00000]

This is the way I would do it.

 

while (true) :
  temp = int(input("Temperature: "))
  if temp < 42:
     print("Too cold!")
  elif temp > 42:
    print("Too hot!")
  elif temp == 42:
    print("Just right")
    break

 

 

 

------------------------------

But, another way of doing it would be this:

 

temp = int(input("Temperature: "))   Get the users input
while (temp != 42 ):                         Make sure it is not 42
  if temp < 42:
     print("Too cold!")
  elif temp > 42:
    print("Too hot!")
  temp = int(input("Temperature: "))
print ("Just right")                             When it is 42, we just print "just right"
 

[Kiwi00000]

Yes, I do agree, I have tested for truth. Which is wrong.

 

It should actually be

 

while (true) :
  temp = int(input("Temperature: "))
  if temp < 42:
     print("Too cold!")
  elif temp > 42:
    print("Too hot!")
  else:
    print("Just right")
    break

 

Sorry about that mistake.

[fizzlesticks]

Personally I would go with

 

while (lambda x: print("Too cold!") or 1 if x < 42 else print("Too hot!") or 1 if x > 42 else print("Just right"))(int(input("Temperature: "))): pass

 

 

Don't do that.

[madknight3]

An alternate approach is to use an infinite loop, but using a break; statement for the condition if temp==42, after printing out "Just right". 

True, but why modify a line that doesn't need changing and add a new line when you don't have to

 

Although I suppose then you'd have to initialize temp anyway for it to enter the loop. Eh, whatever, it's a simple problem so it doesn't really matter.